(5x^2+40x+37)/(x+7)

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Solution for (5x^2+40x+37)/(x+7) equation: 


D( x )

x+7 = 0

x+7 = 0

x+7 = 0

x+7 = 0 // - 7

x = -7

x in (-oo:-7) U (-7:+oo)

(5*x^2+40*x+37)/(x+7) = 0

5*x^2+40*x+37 = 0

5*x^2+40*x+37 = 0

DELTA = 40^2-(4*5*37)

DELTA = 860

DELTA > 0

x = (860^(1/2)-40)/(2*5) or x = (-860^(1/2)-40)/(2*5)

x = (2*215^(1/2)-40)/10 or x = (-2*215^(1/2)-40)/10

(x-((-2*215^(1/2)-40)/10))*(x-((2*215^(1/2)-40)/10)) = 0

((x-((-2*215^(1/2)-40)/10))*(x-((2*215^(1/2)-40)/10)))/(x+7) = 0

( x-((-2*215^(1/2)-40)/10) )

x-((-2*215^(1/2)-40)/10) = 0 // + (-2*215^(1/2)-40)/10

x = (-2*215^(1/2)-40)/10

( x-((2*215^(1/2)-40)/10) )

x-((2*215^(1/2)-40)/10) = 0 // + (2*215^(1/2)-40)/10

x = (2*215^(1/2)-40)/10

x in { (-2*215^(1/2)-40)/10, (2*215^(1/2)-40)/10 }

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